What is the domain of g(x)=\sqrt[4]{x^2-3x} ?

The domain of g(x)=\sqrt[4]{x^2-3x} is x = 3

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domain of g(x)=\sqrt[4]{x^2-3x}

domain

g (x) = 4 x^{2} - 3 x

x \leq 0 or x \geq 3

Interval Notation

(- \infty, 0] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 3

The function domain

x \leq 0 or x \geq 3

f (x) = x^{2} - 4 + 3

\frac{x}{7}

f (x) = 3 x^{2} + x - 8

f (x) = \frac{x ^{2} + 2 x - 5}{x ^{3} - 4 x ^{2} + 3 x}

f (x) = 3 x^{2} + x - 1

What is the domain of g(x)=\sqrt[4]{x^2-3x} ?
The domain of g(x)=\sqrt[4]{x^2-3x} is x<= 0\lor x>= 3