What is the domain of f(x)=(x^2+2x-5)/(x^3-4x^2+3x) ?

The domain of f(x)=(x^2+2x-5)/(x^3-4x^2+3x) is x 3

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domain of f(x)=(x^2+2x-5)/(x^3-4x^2+3x)

domain

f (x) = \frac{x ^{2} + 2 x - 5}{x ^{3} - 4 x ^{2} + 3 x}

x < 0 or 0 < x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1, x = 3

The function domain

x < 0 or 0 < x < 1 or 1 < x < 3 or x > 3

f (x) = 3 x^{2} + x - 1

lo g_{10} (3 x + 6)

f (- 3) = \frac{2 x ^{2}}{3 x - 5}

5 x + 15

1.2 x (\frac{700 - 66 x}{55.2})

What is the domain of f(x)=(x^2+2x-5)/(x^3-4x^2+3x) ?
The domain of f(x)=(x^2+2x-5)/(x^3-4x^2+3x) is x<0\lor 0<x<1\lor 1<x<3\lor x>3