What is the domain of y= 1/(sqrt(2x^2-3x+4)) ?

The domain of y= 1/(sqrt(2x^2-3x+4)) is -infinity <x<infinity

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domain of y= 1/(sqrt(2x^2-3x+4))

domain

y = \frac{1}{2 x ^{2} - 3 x + 4}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 3 \frac{y}{y - 2}

\frac{x ^{2} - 3}{x ^{2} + 1}

y = lo g_{10} (2 x)

f (x) = ln (\frac{4 - x}{2 + 2 x})

f (x) = 3 x^{2} + 1

What is the domain of y= 1/(sqrt(2x^2-3x+4)) ?
The domain of y= 1/(sqrt(2x^2-3x+4)) is -infinity <x<infinity