What is the domain of g(x)=(x^2)/((x-3)(x+4)(x+1)) ?

The domain of g(x)=(x^2)/((x-3)(x+4)(x+1)) is x 3

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domain of g(x)=(x^2)/((x-3)(x+4)(x+1))

domain

g (x) = \frac{x ^{2}}{( x - 3 ) ( x + 4 ) ( x + 1 )}

x < - 4 or - 4 < x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4, x = - 1

The function domain

x < - 4 or - 4 < x < - 1 or - 1 < x < 3 or x > 3

g (x) = \frac{9}{x - 3}

f (x) = \frac{2 + x + x ^{2}}{5 - 2 x}

\frac{x ^{2} + 1}{x ^{4} + 3 x ^{2} + 1}

f (x) = \frac{x ^{2}}{x ^{2} + x - 2}

x^{4} e^{- x}

What is the domain of g(x)=(x^2)/((x-3)(x+4)(x+1)) ?
The domain of g(x)=(x^2)/((x-3)(x+4)(x+1)) is x<-4\lor-4<x<-1\lor-1<x<3\lor x>3