What is the domain of sqrt(2ln(x-1)) ?

The domain of sqrt(2ln(x-1)) is x>= 2

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domain of sqrt(2ln(x-1))

domain

2 ln (x - 1)

x \geq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = x^{2} - 2 x, x \geq 1

5 x^{2} + 4

f (x) = \frac{7 x + 1}{2 x ^{2} + 3 x}

2 x^{2} - 24 x + 64

f (x) = 3 - (\frac{13}{x ^{2} + 5})