What is the domain of f(x)=(7x+1)/(2x^2+3x) ?

The domain of f(x)=(7x+1)/(2x^2+3x) is x 0

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domain of f(x)=(7x+1)/(2x^2+3x)

domain

f (x) = \frac{7 x + 1}{2 x ^{2} + 3 x}

x < - \frac{3}{2} or - \frac{3}{2} < x < 0 or x > 0

Interval Notation

(- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - \frac{3}{2}

The function domain

x < - \frac{3}{2} or - \frac{3}{2} < x < 0 or x > 0

2 x^{2} - 24 x + 64

f (x) = 3 - (\frac{13}{x ^{2} + 5})

f (x) = \frac{8 - x}{x + 3}

\frac{1}{x ^{2}} - 1

f (x) = \frac{- 3 x}{x - 1}

What is the domain of f(x)=(7x+1)/(2x^2+3x) ?
The domain of f(x)=(7x+1)/(2x^2+3x) is x<-3/2 \lor-3/2 <x<0\lor x>0