What is the domain of f(x)=sqrt(60x+4500) ?

The domain of f(x)=sqrt(60x+4500) is x>=-75

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domain of f(x)=sqrt(60x+4500)

domain

f (x) = 60 x + 4500

x \geq - 75

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 75

The function domain

x \geq - 75

2 - x - lo g_{5} (12 - x^{2})

\frac{3 x + 1}{x}

f (x) = - \frac{16}{15} x + \frac{8}{15}

y = - 2 x - 7 + 1

f (x) = \frac{x + 7}{x ^{2} + 3 x - 4}

What is the domain of f(x)=sqrt(60x+4500) ?
The domain of f(x)=sqrt(60x+4500) is x>=-75