What is the domain of f(x)= x/((1+x)^2) ?

The domain of f(x)= x/((1+x)^2) is x -1

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domain of f(x)= x/((1+x)^2)

domain

f (x) = \frac{x}{( 1 + x ) ^{2}}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = 12 - x - \frac{9}{x}, x > 0

(x - 1)^{2} + 5

(x - 1)^{2} + 3

f (x) = lo g_{3} (8 - 2 x) + 1

(\frac{1}{2})^{x - 2} - 2

What is the domain of f(x)= x/((1+x)^2) ?
The domain of f(x)= x/((1+x)^2) is x<-1\lor x>-1