What is the domain of f(x)=log_{3}(8-2x)+1 ?

The domain of f(x)=log_{3}(8-2x)+1 is x<4

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domain of f(x)=log_{3}(8-2x)+1

domain

f (x) = lo g_{3} (8 - 2 x) + 1

x < 4

Interval Notation

(- \infty, 4)

Solution steps

Find positive values for logs:

x < 4

The function domain

x < 4

(\frac{1}{2})^{x - 2} - 2

f (x) = \frac{( x + 3 )}{4}

f (x) = 1^{x}

f (x) = \frac{x ^{3} + 4}{x ^{2} - 25}

\frac{( x ^{3} - x ^{2} - 13 x - 3 )}{( x + 3 )}

What is the domain of f(x)=log_{3}(8-2x)+1 ?
The domain of f(x)=log_{3}(8-2x)+1 is x<4