What is the domain of f(x)=log_{3}(2x-5) ?

The domain of f(x)=log_{3}(2x-5) is x> 5/2

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domain of f(x)=log_{3}(2x-5)

domain

f (x) = lo g_{3} (2 x - 5)

x > \frac{5}{2}

Interval Notation

(\frac{5}{2}, \infty)

Solution steps

Find positive values for logs:

x > \frac{5}{2}

The function domain

x > \frac{5}{2}

y = \frac{2}{3} + x

f (x) = - \frac{x}{x ^{2} + x}

4 + 8 x - 6 x^{2}

f (x) = \frac{3 x}{∣ x ∣}

f (x) = 64 - x^{2} - x + 2

What is the domain of f(x)=log_{3}(2x-5) ?
The domain of f(x)=log_{3}(2x-5) is x> 5/2