What is the domain of y=5tan(x) ?

The domain of y=5tan(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of y=5tan(x)

domain

y = 5 tan (x)

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Interval Notation

Solution steps

Take the denominator(s) of

5 tan (x)

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

5 tan (x) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

f (x) = 2^{(x - 5)} - 11

f (x) = ln (3 x - x^{2})

3 1 - x

f (x) = 2 x^{2} - 3 x - 2

f (x) = arcsin (1 - x)

What is the domain of y=5tan(x) ?
The domain of y=5tan(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin