What is the domain of sqrt(72-x^2+x) ?

The domain of sqrt(72-x^2+x) is -8<= x<= 9

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domain of sqrt(72-x^2+x)

domain

72 - x^{2} + x

- 8 \leq x \leq 9

Interval Notation

[- 8, 9]

Solution steps

Find non-negative values for radicals:

- 8 \leq x \leq 9

The function domain

- 8 \leq x \leq 9

2 - 3 X

f (x) = 5 - x + 3 x - 1

f (x) = ln (\frac{1}{x - 6})

y = 2 x + 3

f (x) = (\frac{4 x}{5 ( x - 2 ) ( x - 7 )})

What is the domain of sqrt(72-x^2+x) ?
The domain of sqrt(72-x^2+x) is -8<= x<= 9