What is the domain of ln(sqrt(3x-2)) ?

The domain of ln(sqrt(3x-2)) is x> 2/3

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domain of ln(sqrt(3x-2))

domain

ln (3 x - 2)

x > \frac{2}{3}

Interval Notation

(\frac{2}{3}, \infty)

Solution steps

Find positive values for logs:

x > \frac{2}{3}

The function domain

x > \frac{2}{3}

\frac{x ^{2} - 8 x - 9}{2 x ^{2} - x - 10}

y = \frac{6}{3 - x}

f (x) = \frac{7}{16 - x ^{2}}

f (x) = - 2 x^{2} - 4 + ln (- 5 - 2 x)

\frac{x + 5}{4 x - 2}