What is the domain of (x^2-8x-9)/(2x^2-x-10) ?

The domain of (x^2-8x-9)/(2x^2-x-10) is x 5/2

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domain of (x^2-8x-9)/(2x^2-x-10)

domain

\frac{x ^{2} - 8 x - 9}{2 x ^{2} - x - 10}

x < - 2 or - 2 < x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

(- \infty, - 2) \cup (- 2, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{2}, x = - 2

The function domain

x < - 2 or - 2 < x < \frac{5}{2} or x > \frac{5}{2}

y = \frac{6}{3 - x}

f (x) = \frac{7}{16 - x ^{2}}

f (x) = - 2 x^{2} - 4 + ln (- 5 - 2 x)

\frac{x + 5}{4 x - 2}

\frac{y}{3 y ^{2} + 17 y + 10}

What is the domain of (x^2-8x-9)/(2x^2-x-10) ?
The domain of (x^2-8x-9)/(2x^2-x-10) is x<-2\lor-2<x< 5/2 \lor x> 5/2