What is the domain of f(x)=(10)/(9-x^2) ?

The domain of f(x)=(10)/(9-x^2) is x 3

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domain of f(x)=(10)/(9-x^2)

domain

f (x) = \frac{10}{9 - x ^{2}}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = \frac{x + 3}{x ^{2} + 9 x + 18}

f (x) = 2 x^{2} + 8 x - 5

f (x) = 9 x + 2

f (x) = ln (\frac{4 x - 8}{2 x + 4})

f (x) = 2 x^{2} + 8 x + 1

What is the domain of f(x)=(10)/(9-x^2) ?
The domain of f(x)=(10)/(9-x^2) is x<-3\lor-3<x<3\lor x>3