What is the domain of 1/((x-3)(x-5)) ?

The domain of 1/((x-3)(x-5)) is x 5

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domain of 1/((x-3)(x-5))

domain

\frac{1}{( x - 3 ) ( x - 5 )}

x < 3 or 3 < x < 5 or x > 5

Interval Notation

(- \infty, 3) \cup (3, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 5

The function domain

x < 3 or 3 < x < 5 or x > 5

+ 500 x - 10 x^{2}

f (x) = \frac{sin ^{2} ( x ) - 1}{cos ( 2 x )}

f (x) = ln (x^{2}) - ln (2 x + 8)

f (x, y) = 3

f (x) = (x^{2} - 6 x)^{\frac{1}{5}}

What is the domain of 1/((x-3)(x-5)) ?
The domain of 1/((x-3)(x-5)) is x<3\lor 3<x<5\lor x>5