What is the domain of 1/((x+2)^2)+4 ?

The domain of 1/((x+2)^2)+4 is x -2

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domain of 1/((x+2)^2)+4

domain

\frac{1}{( x + 2 ) ^{2}} + 4

x < - 2 or x > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2

The function domain

x < - 2 or x > - 2

y = 1 - \frac{x + 1}{x - 1}

f (x) = - 50 x - 55

f (x) = (x - 5)^{2}

1 + \frac{9 x - 70}{x ^{2} - 15 x + 56}

f (x) = \frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

What is the domain of 1/((x+2)^2)+4 ?
The domain of 1/((x+2)^2)+4 is x<-2\lor x>-2