What is the domain of y=sqrt(9-x^2)+3 ?

The domain of y=sqrt(9-x^2)+3 is -3<= x<= 3

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domain of y=sqrt(9-x^2)+3

domain

y = 9 - x^{2} + 3

- 3 \leq x \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

The function domain

- 3 \leq x \leq 3

\frac{x - 2}{x ^{2} + x - 6}

f (x) = 3 - \frac{4}{x ^{3}}

f (x) = \frac{1 + x ^{4}}{x ^{2} - x ^{4}}

f (x) = - e^{x - 2}

f (x) = - (x - 1)^{3} (x + 3)^{2}

What is the domain of y=sqrt(9-x^2)+3 ?
The domain of y=sqrt(9-x^2)+3 is -3<= x<= 3