What is the domain of f(x)=sqrt(-x^2+6x) ?

The domain of f(x)=sqrt(-x^2+6x) is 0<= x<= 6

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domain of f(x)=sqrt(-x^2+6x)

domain

f (x) = - x^{2} + 6 x

0 \leq x \leq 6

Interval Notation

[0, 6]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 6

The function domain

0 \leq x \leq 6

lo g_{2} (x (2 x - 3))

y 2 (x - 1) (x - 3) = 4

4^{x} - 1

\frac{4 x - 12}{3}

f (x) = \frac{2 x - 5}{x ^{2} - 6 x}

What is the domain of f(x)=sqrt(-x^2+6x) ?
The domain of f(x)=sqrt(-x^2+6x) is 0<= x<= 6