What is the domain of f(x)= 1/(9x+6) ?

The domain of f(x)= 1/(9x+6) is x -2/3

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domain of f(x)= 1/(9x+6)

domain

f (x) = \frac{1}{9 x + 6}

x < - \frac{2}{3} or x > - \frac{2}{3}

Interval Notation

(- \infty, - \frac{2}{3}) \cup (- \frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{2}{3}

The function domain

x < - \frac{2}{3} or x > - \frac{2}{3}

f (x) = \frac{x + 6}{( x - 2 ) ( x + 3 )}

f (x) = \frac{x ^{2} + 2}{x - 7}

f (x) = \frac{2 x + 2}{3 x + 10}

\frac{x ^{2} - 2 x + 6}{( x ^{2} + 2 ) ( x - 2 )}

f (x) = 3 \cdot x^{\frac{2}{3}} - 2 x

What is the domain of f(x)= 1/(9x+6) ?
The domain of f(x)= 1/(9x+6) is x<-2/3 \lor x>-2/3