What is the domain of (25-e^{x^2})/(1-e^{25-x^2)} ?

The domain of (25-e^{x^2})/(1-e^{25-x^2)} is x 5

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domain of (25-e^{x^2})/(1-e^{25-x^2)}

domain

\frac{25 - e ^{x^{2}}}{1 - e ^{25 - x^{2}}}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = \frac{x - 7}{x ^{2}}

\frac{2}{x + 1} + (\frac{x}{x + 1})

(16 - x)^{4}

f (x) = \frac{x}{ln ( - x - 2 )}

f (x) = \frac{4 - x ^{2}}{x ( x ^{2} - 9 )}

What is the domain of (25-e^{x^2})/(1-e^{25-x^2)} ?
The domain of (25-e^{x^2})/(1-e^{25-x^2)} is x<-5\lor-5<x<5\lor x>5