What is the domain of f(x)=(sqrt(4-x^2))/(x(x^2-9)) ?

The domain of f(x)=(sqrt(4-x^2))/(x(x^2-9)) is -2<= x<0\lor 0<x<= 2

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domain of f(x)=(sqrt(4-x^2))/(x(x^2-9))

domain

f (x) = \frac{4 - x ^{2}}{x ( x ^{2} - 9 )}

- 2 \leq x < 0 or 0 < x \leq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 0, x = - 3, x = 3

Combine real regions and undefined points for final function domain

- 2 \leq x < 0 or 0 < x \leq 2

f (x) = 2 x + 4 - 3

f (x) = 3 5 x^{3} + 40

f (x) = \frac{1 x ^{2} + 4}{x + 6}

f (x) = \frac{1}{x} - 2

9 x + 6

What is the domain of f(x)=(sqrt(4-x^2))/(x(x^2-9)) ?
The domain of f(x)=(sqrt(4-x^2))/(x(x^2-9)) is -2<= x<0\lor 0<x<= 2