What is the domain of f(x)=(1x^2+4)/(x+6) ?

The domain of f(x)=(1x^2+4)/(x+6) is x -6

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domain of f(x)=(1x^2+4)/(x+6)

domain

f (x) = \frac{1 x ^{2} + 4}{x + 6}

x < - 6 or x > - 6

Interval Notation

(- \infty, - 6) \cup (- 6, \infty)

Solution steps

Find undefined (singularity) points:

x = - 6

The function domain

x < - 6 or x > - 6

f (x) = \frac{1}{x} - 2

9 x + 6

\frac{( - x + ( 9 x ^{2} + 8 x ) )}{2 x}

2 (π) (r^{2}) + 12 (π) (r)

x^{3} + 2 x + 5

What is the domain of f(x)=(1x^2+4)/(x+6) ?
The domain of f(x)=(1x^2+4)/(x+6) is x<-6\lor x>-6