What is the domain of f(x)=sqrt(1/x-2) ?

The domain of f(x)=sqrt(1/x-2) is 0<x<= 1/2

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domain of f(x)=sqrt(1/x-2)

domain

f (x) = \frac{1}{x} - 2

0 < x \leq \frac{1}{2}

Interval Notation

Solution steps

Find non-negative values for radicals:

0 < x \leq \frac{1}{2}

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

0 < x \leq \frac{1}{2}

9 x + 6

\frac{( - x + ( 9 x ^{2} + 8 x ) )}{2 x}

2 (π) (r^{2}) + 12 (π) (r)

x^{3} + 2 x + 5

f (x) = \frac{1}{( x - 1 ) ( x + 3 )}

What is the domain of f(x)=sqrt(1/x-2) ?
The domain of f(x)=sqrt(1/x-2) is 0<x<= 1/2