What is the domain of f(x)=sqrt(3x^2-6x) ?

The domain of f(x)=sqrt(3x^2-6x) is x = 2

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domain of f(x)=sqrt(3x^2-6x)

domain

f (x) = 3 x^{2} - 6 x

x \leq 0 or x \geq 2

Interval Notation

(- \infty, 0] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

The function domain

x \leq 0 or x \geq 2

f (x) = 36 - x^{2} - x + 2

f (x) = \frac{x - 7}{x - 5}, x < 7

7 - 4 x

f (x) = lo g_{10} (\frac{1}{2}) (4 - ∣ x ∣)

f (x) = \frac{x ^{3}}{x - 2}

What is the domain of f(x)=sqrt(3x^2-6x) ?
The domain of f(x)=sqrt(3x^2-6x) is x<= 0\lor x>= 2