What is the domain of y=sqrt(t-16) ?

The domain of y=sqrt(t-16) is t>= 16

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domain of y=sqrt(t-16)

domain

y = t - 16

t \geq 16

Interval Notation

Solution steps

Find non-negative values for radicals:

t \geq 16

The function domain

t \geq 16

f (x) = arcsin (- y)

f (x) = \frac{1}{2 x - 4}

e^{x + 3} + 4

\frac{x ^{2} - 3}{5 x ^{2} + 2 x + 1}

f (x) = x^{2} + 8, x \geq 0