What is the domain of f(x)= 1/(sqrt(2x)-4) ?

The domain of f(x)= 1/(sqrt(2x)-4) is 0 8

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domain of f(x)= 1/(sqrt(2x)-4)

domain

f (x) = \frac{1}{2 x - 4}

0 \leq x < 8 or x > 8

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

0 \leq x < 8 or x > 8

e^{x + 3} + 4

\frac{x ^{2} - 3}{5 x ^{2} + 2 x + 1}

f (x) = x^{2} + 8, x \geq 0

\frac{ln ( x - 2 ) - 3}{4}

\frac{8 x - 12}{4 + 3 x}

What is the domain of f(x)= 1/(sqrt(2x)-4) ?
The domain of f(x)= 1/(sqrt(2x)-4) is 0<= x<8\lor x>8