What is the domain of (sqrt(x^2-16))/(x-3) ?

The domain of (sqrt(x^2-16))/(x-3) is x = 4

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domain of (sqrt(x^2-16))/(x-3)

domain

\frac{x ^{2} - 16}{x - 3}

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \leq - 4 or x \geq 4

f (x) = 3 x^{2} - 3 x + 1

3 t - 3

f (0) = x - 1

\frac{x + 5}{2} + 3

f (x) = \frac{x + 4}{x ^{2} - x - 6}

What is the domain of (sqrt(x^2-16))/(x-3) ?
The domain of (sqrt(x^2-16))/(x-3) is x<=-4\lor x>= 4