What is the domain of f(x)=sqrt(2x-1)(1/2) ?

The domain of f(x)=sqrt(2x-1)(1/2) is x>= 1/2

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domain of f(x)=sqrt(2x-1)(1/2)

domain

f (x) = 2 x - 1 (\frac{1}{2})

x \geq \frac{1}{2}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

The function domain

x \geq \frac{1}{2}

f (x) = \frac{2 x}{( 9 - x ^{2} ) ^{2}}

f (x) = (4 - 5 x^{3})^{- 2}

f (x) = \frac{9 x - 5}{x ^{2} - 9 x + 8}

\frac{x ^{2} - 2 x}{x + 3}

y = 3 t^{2} - 2 t + 1

What is the domain of f(x)=sqrt(2x-1)(1/2) ?
The domain of f(x)=sqrt(2x-1)(1/2) is x>= 1/2