What is the domain of f(x)=(2x)/((9-x^2)^2) ?

The domain of f(x)=(2x)/((9-x^2)^2) is x 3

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domain of f(x)=(2x)/((9-x^2)^2)

domain

f (x) = \frac{2 x}{( 9 - x ^{2} ) ^{2}}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = (4 - 5 x^{3})^{- 2}

f (x) = \frac{9 x - 5}{x ^{2} - 9 x + 8}

\frac{x ^{2} - 2 x}{x + 3}

y = 3 t^{2} - 2 t + 1

\frac{x ^{2} + 2 x - 8}{x ^{2} + 5 x + 4}

What is the domain of f(x)=(2x)/((9-x^2)^2) ?
The domain of f(x)=(2x)/((9-x^2)^2) is x<-3\lor-3<x<3\lor x>3