What is the domain of (x^2+2x-8)/(x^2+5x+4) ?

The domain of (x^2+2x-8)/(x^2+5x+4) is x -1

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domain of (x^2+2x-8)/(x^2+5x+4)

domain

\frac{x ^{2} + 2 x - 8}{x ^{2} + 5 x + 4}

x < - 4 or - 4 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 4) \cup (- 4, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 4

The function domain

x < - 4 or - 4 < x < - 1 or x > - 1

(6.8) (- 3.8) (- 6.8)

G (t) = \frac{( 3 t - 2 )}{( 3 - 4 t )}

f (x) = ∣ 2 x ∣ - 5

\frac{1}{( x - 3 ) ( x - 5 ) ^{2}}

\frac{9 x + 7}{x - 3}

What is the domain of (x^2+2x-8)/(x^2+5x+4) ?
The domain of (x^2+2x-8)/(x^2+5x+4) is x<-4\lor-4<x<-1\lor x>-1