What is the domain of 1/((x-3)(x-5)^2) ?

The domain of 1/((x-3)(x-5)^2) is x 5

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domain of 1/((x-3)(x-5)^2)

domain

\frac{1}{( x - 3 ) ( x - 5 ) ^{2}}

x < 3 or 3 < x < 5 or x > 5

Interval Notation

(- \infty, 3) \cup (3, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 5

The function domain

x < 3 or 3 < x < 5 or x > 5

\frac{9 x + 7}{x - 3}

\frac{3 x - 6}{x ^{3} - 6}

f (x) = \frac{( x + 9 )}{( x ^{2} - 81 )}

f (x) = \frac{4 x ^{2} + 4}{∣ 2 x ^{2} - 8 ∣}

f (x) = \frac{( 1 + x )}{e ^{c o s (x)}}

What is the domain of 1/((x-3)(x-5)^2) ?
The domain of 1/((x-3)(x-5)^2) is x<3\lor 3<x<5\lor x>5