What is the domain of f(x)=sqrt((x^2+1)/(x^2-3x+4)) ?

The domain of f(x)=sqrt((x^2+1)/(x^2-3x+4)) is -infinity <x<infinity

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domain of f(x)=sqrt((x^2+1)/(x^2-3x+4))

domain

f (x) = \frac{x ^{2} + 1}{x ^{2} - 3 x + 4}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

h (x) = x - 7 + 5

y = \frac{x + 4}{x ^{2} - 3}

f (x) = ln (\frac{2 - x}{x + 2})

f (x) = \frac{7}{4 x + 2}

f (x) = \frac{6 - 8 x}{x - 9}

What is the domain of f(x)=sqrt((x^2+1)/(x^2-3x+4)) ?
The domain of f(x)=sqrt((x^2+1)/(x^2-3x+4)) is -infinity <x<infinity