What is the domain of y= x/(sqrt(x^2+2x+2)) ?

The domain of y= x/(sqrt(x^2+2x+2)) is -infinity <x<infinity

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domain of y= x/(sqrt(x^2+2x+2))

domain

y = \frac{x}{x ^{2} + 2 x + 2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x^{2} + 3 x - x

f (x) = 2 + x + 2

f (x) = lo g_{2} (x - 6)

f (x) = \frac{( x - 3 )}{( 2 x ^{2} + 10 x )}

f (x) = ∣ x - 2 ∣ - ∣ x + 2 ∣

What is the domain of y= x/(sqrt(x^2+2x+2)) ?
The domain of y= x/(sqrt(x^2+2x+2)) is -infinity <x<infinity