What is the domain of f(x)=((x-3))/((2x^2+10x)) ?

The domain of f(x)=((x-3))/((2x^2+10x)) is x 0

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domain of f(x)=((x-3))/((2x^2+10x))

domain

f (x) = \frac{( x - 3 )}{( 2 x ^{2} + 10 x )}

x < - 5 or - 5 < x < 0 or x > 0

Interval Notation

(- \infty, - 5) \cup (- 5, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 5

The function domain

x < - 5 or - 5 < x < 0 or x > 0

f (x) = ∣ x - 2 ∣ - ∣ x + 2 ∣

\frac{1}{20 x ^{2}}

f (x) = \frac{2 x ^{2} + 10 x + 8}{x - 2}

f (x) = \frac{x}{∣ x ∣ + 1}

\frac{5 + 7 x}{x - 1}

What is the domain of f(x)=((x-3))/((2x^2+10x)) ?
The domain of f(x)=((x-3))/((2x^2+10x)) is x<-5\lor-5<x<0\lor x>0