What is the domain of sqrt((9-x^2)(x+1)) ?

The domain of sqrt((9-x^2)(x+1)) is x<=-3\lor-1<= x<= 3

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domain of sqrt((9-x^2)(x+1))

domain

(9 - x^{2}) (x + 1)

x \leq - 3 or - 1 \leq x \leq 3

Interval Notation

(- \infty, - 3] \cup [- 1, 3]

Solution steps

Find non-negative values for radicals:

x \leq - 3 or - 1 \leq x \leq 3

The function domain

x \leq - 3 or - 1 \leq x \leq 3

f (x) = \frac{x ^{2} - 1}{x + 1} - x^{3} - x

\frac{x - 7}{x + 2}

y = 1 - ∣ x ∣

f (x) = \frac{x}{x + 5}

\frac{4}{2 x ^{2} - 3}

What is the domain of sqrt((9-x^2)(x+1)) ?
The domain of sqrt((9-x^2)(x+1)) is x<=-3\lor-1<= x<= 3