What is the domain of 4/(2x^2-3) ?

The domain of 4/(2x^2-3) is x sqrt(3/2)

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domain of 4/(2x^2-3)

domain

\frac{4}{2 x ^{2} - 3}

x < - \frac{3}{2} or - \frac{3}{2} < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}, x = - \frac{3}{2}

The function domain

x < - \frac{3}{2} or - \frac{3}{2} < x < \frac{3}{2} or x > \frac{3}{2}

lo g_{10} (2 x^{2} - 5 x + 3)

1 + 8^{- x}

y = 2 (2)^{x + 4} - 1

y = ∣ x ∣

f (x) = \frac{x + 1}{2 x ^{2} + 7 x - 9}

What is the domain of 4/(2x^2-3) ?
The domain of 4/(2x^2-3) is x<-sqrt(3/2)\lor-sqrt(3/2)<x<sqrt(3/2)\lor x>sqrt(3/2)