What is the domain of f(x)=sqrt(1-ln(x)) ?

The domain of f(x)=sqrt(1-ln(x)) is 0<x<= e

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domain of f(x)=sqrt(1-ln(x))

domain

f (x) = 1 - ln (x)

0 < x \leq e

Interval Notation

(0, e]

Solution steps

Find non-negative values for radicals:

0 < x \leq e

The function domain

0 < x \leq e

y = x x^{2} - 2

+ x - 2

f (x) = \frac{1}{x + 7} + 9

f (x) = \frac{1}{2 x} \cdot \frac{x}{x - 1}

f (x) = \frac{x ^{2} - 2 x}{x - 3}

What is the domain of f(x)=sqrt(1-ln(x)) ?
The domain of f(x)=sqrt(1-ln(x)) is 0<x<= e