What is the domain of f(x)=(sqrt(x+2))/(sqrt(9-x)) ?

The domain of f(x)=(sqrt(x+2))/(sqrt(9-x)) is -2<= x<9

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domain of f(x)=(sqrt(x+2))/(sqrt(9-x))

domain

f (x) = \frac{x + 2}{9 - x}

- 2 \leq x < 9

Interval Notation

[- 2, 9)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

- 2 \leq x < 9

\frac{1}{\frac{1}{x - 3}}

(\frac{1}{3})^{x - 2} + 4

y = \frac{4 - x ^{2}}{x ^{2} - x - 6}

f (x) = x e^{s i n (x)}

2 x^{2} + 4 x - 5

What is the domain of f(x)=(sqrt(x+2))/(sqrt(9-x)) ?
The domain of f(x)=(sqrt(x+2))/(sqrt(9-x)) is -2<= x<9