What is the domain of f(t)= 1/(t-3) ?

The domain of f(t)= 1/(t-3) is t 3

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domain of f(t)= 1/(t-3)

domain

f (t) = \frac{1}{t - 3}

t < 3 or t > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

t = 3

The function domain

t < 3 or t > 3

\frac{3}{( x + 1 ) ^{2}}

f (t) = t ln (\frac{1}{t})

h (x) = \frac{x - 3}{x ^{3} - 9 x}

f (x) = \frac{( x + 5 )}{( x ^{2} + 5 x + 6 )}

f (x) = \frac{x - 2}{x + 4}

What is the domain of f(t)= 1/(t-3) ?
The domain of f(t)= 1/(t-3) is t<3\lor t>3