What is the domain of f(x)=5x-3f(x)=(9x^2-4)/(3x+2) ?

The domain of f(x)=5x-3f(x)=(9x^2-4)/(3x+2) is x -2/3

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domain of f(x)=5x-3f(x)=(9x^2-4)/(3x+2)

domain

f (x) = 5 x - 3 f (x) = \frac{9 x ^{2} - 4}{3 x + 2}

x < - \frac{2}{3} or x > - \frac{2}{3}

Interval Notation

(- \infty, - \frac{2}{3}) \cup (- \frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{2}{3}

The function domain

x < - \frac{2}{3} or x > - \frac{2}{3}

f (x) = x^{2} + 4 x - 12

g (x) = \frac{x + 7}{x ^{2} - 49}

f (x) = lo g_{\frac{1}{4}} (x^{2} - 4 x + 4)

5 - 2 x^{2}

f (x) = \frac{2 x - 6}{x ^{2} - 6 x}

What is the domain of f(x)=5x-3f(x)=(9x^2-4)/(3x+2) ?
The domain of f(x)=5x-3f(x)=(9x^2-4)/(3x+2) is x<-2/3 \lor x>-2/3