What is the domain of 3/((\frac{5){x-1})+4} ?

The domain of 3/((\frac{5){x-1})+4} is x 1

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domain of 3/((\frac{5){x-1})+4}

domain

\frac{3}{( \frac{5}{x - 1} ) + 4}

x < - \frac{1}{4} or - \frac{1}{4} < x < 1 or x > 1

Interval Notation

(- \infty, - \frac{1}{4}) \cup (- \frac{1}{4}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{4}, x = 1

The function domain

x < - \frac{1}{4} or - \frac{1}{4} < x < 1 or x > 1

y = x^{3} + 3 x^{2}

f (x) = 4 x^{5} + 16 x^{2} + 8

(- 5 x)^{5}

f (x) = \frac{x ^{2} + 1}{x ^{2} - 9}

f (x) = 4 + 2 x + 1

What is the domain of 3/((\frac{5){x-1})+4} ?
The domain of 3/((\frac{5){x-1})+4} is x<-1/4 \lor-1/4 <x<1\lor x>1