What is the domain of f(x)=(x^2+3x+2)/(x^2+4x+3) ?

The domain of f(x)=(x^2+3x+2)/(x^2+4x+3) is x -1

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domain of f(x)=(x^2+3x+2)/(x^2+4x+3)

domain

f (x) = \frac{x ^{2} + 3 x + 2}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

\frac{4 x}{x + 3}

\frac{1}{3} (x - 5)

f (x) = lo g_{\frac{1}{9}} (9 x - 1)

∣ x + 2 ∣ - ∣ x - 1 ∣ + ∣ x - 4 ∣

y = \frac{x ^{2} - 25}{x + 5}

What is the domain of f(x)=(x^2+3x+2)/(x^2+4x+3) ?
The domain of f(x)=(x^2+3x+2)/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1