What is the domain of f(x)=log_{1/9}(9x-1) ?

The domain of f(x)=log_{1/9}(9x-1) is x> 1/9

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domain of f(x)=log_{1/9}(9x-1)

domain

f (x) = lo g_{\frac{1}{9}} (9 x - 1)

x > \frac{1}{9}

Interval Notation

(\frac{1}{9}, \infty)

Solution steps

Find positive values for logs:

x > \frac{1}{9}

The function domain

x > \frac{1}{9}

∣ x + 2 ∣ - ∣ x - 1 ∣ + ∣ x - 4 ∣

y = \frac{x ^{2} - 25}{x + 5}

f (x) = lo g_{10} (5) (x - 2) + 1

\frac{x ^{2}}{( x - 4 ) ( x + 3 ) ( x - 1 )}

h (t) = \frac{cos ^{2} ( t )}{1 - t ^{2}}

What is the domain of f(x)=log_{1/9}(9x-1) ?
The domain of f(x)=log_{1/9}(9x-1) is x> 1/9