What is the domain of ln(1/(x+3)) ?

The domain of ln(1/(x+3)) is x>-3

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domain of ln(1/(x+3))

domain

ln (\frac{1}{x + 3})

x > - 3

Interval Notation

(- 3, \infty)

Solution steps

Find positive values for logs:

x > - 3

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x > - 3

y = \frac{x ^{2} - 5 x + 6}{x - 4}

f (x) = \frac{2}{3 x ^{2}}

g (x) = lo g_{4} (x + 2) - 1

f (x) = \frac{3 x - 5}{4 - x}

y = \frac{x ^{2}}{x ^{2} + 1}