What is the domain of y=(sqrt(x^2-5x+6))/(x-4) ?

The domain of y=(sqrt(x^2-5x+6))/(x-4) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(sqrt(x^2-5x+6))/(x-4)

domain

y = \frac{x ^{2} - 5 x + 6}{x - 4}

x \leq 2 or 3 \leq x < 4 or x > 4

Interval Notation

(- \infty, 2] \cup [3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 3

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

x \leq 2 or 3 \leq x < 4 or x > 4

f (x) = \frac{2}{3 x ^{2}}

g (x) = lo g_{4} (x + 2) - 1

f (x) = \frac{3 x - 5}{4 - x}

y = \frac{x ^{2}}{x ^{2} + 1}

2 x^{2} - 7

What is the domain of y=(sqrt(x^2-5x+6))/(x-4) ?
The domain of y=(sqrt(x^2-5x+6))/(x-4) is x<= 2\lor 3<= x<4\lor x>4