What is the domain of f(x)= 1/(x^2+4x-60) ?

The domain of f(x)= 1/(x^2+4x-60) is x 6

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domain of f(x)= 1/(x^2+4x-60)

domain

f (x) = \frac{1}{x ^{2} + 4 x - 60}

x < - 10 or - 10 < x < 6 or x > 6

Interval Notation

(- \infty, - 10) \cup (- 10, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 10

The function domain

x < - 10 or - 10 < x < 6 or x > 6

f (x) = \frac{e ^{x}}{1 + e ^{2 x}}

f (x) = 2 t - 3

\frac{x}{18 x ^{2} - 33 x - 40}

f (x) = x + 6 - 8

sin (arccos (x - 1))

What is the domain of f(x)= 1/(x^2+4x-60) ?
The domain of f(x)= 1/(x^2+4x-60) is x<-10\lor-10<x<6\lor x>6