What is the domain of f(x)=sqrt(4x+6) ?

The domain of f(x)=sqrt(4x+6) is x>=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(4x+6)

domain

f (x) = 4 x + 6

x \geq - \frac{3}{2}

Interval Notation

[- \frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{2}

The function domain

x \geq - \frac{3}{2}

\frac{\frac{2}{x + 1}}{\frac{x}{x + 1}}

f (x) = x^{5} - 3 x^{4} + 1

y = 3 x

arccos (3 - 2 x)

f (x) = 8 a x + 1

What is the domain of f(x)=sqrt(4x+6) ?
The domain of f(x)=sqrt(4x+6) is x>=-3/2