What is the domain of ((x^2-x))/(9x) ?

The domain of ((x^2-x))/(9x) is x 0

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domain of ((x^2-x))/(9x)

domain

\frac{( x ^{2} - x )}{9 x}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

cot (θ)

f (x) = \frac{1}{20 - 8 x - x ^{2}}

f (x) = \frac{2 x - 1}{2 x ^{2} - 5 x - 6}

\frac{2 x ^{2}}{x + 1}

f (x) = ln (\frac{x + 4}{4 x - 16})

What is the domain of ((x^2-x))/(9x) ?
The domain of ((x^2-x))/(9x) is x<0\lor x>0