What is the domain of f(x)=log_{3}(2x-1)-2 ?

The domain of f(x)=log_{3}(2x-1)-2 is x> 1/2

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domain of f(x)=log_{3}(2x-1)-2

domain

f (x) = lo g_{3} (2 x - 1) - 2

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find positive values for logs:

x > \frac{1}{2}

The function domain

x > \frac{1}{2}

y = - 4

y = \frac{x ^{2} + x - 6}{x - 2}

y = (x + 3) (x - 1) (x - 4)

- (x + 4)^{3} - 4

t 4 - t^{2}

What is the domain of f(x)=log_{3}(2x-1)-2 ?
The domain of f(x)=log_{3}(2x-1)-2 is x> 1/2